2/3x^2=600

Solution for 2/3x^2=600 equation:

2/3x^2=600

We move all terms to the left:

2/3x^2-(600)=0


Domain of the equation: 3x^2!=0

x^2!=0/3

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


-600*3x^2+2=0

Wy multiply elements

-1800x^2+2=0

a = -1800; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-1800)·2
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*-1800}=\frac{-120}{-3600}
=1/30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*-1800}=\frac{120}{-3600}
=-1/30
$